Question 112

In a farmhouse , there are only horses and sheep. If 50% of the horses were sheep, then there would have been 50% more sheep than the number of horses. What percentage of all the animals are horses?

Assume that there are x horses and y sheep. They both add up to 100%. If 50% of horses were sheep, there would have been 50% more sheep than the number of horses. So, considering horses count as h/2 and sheep count as h/2+s, we can frame the equation (h/2+h/4) = s+h/2. Solving this, we get s=(h/4). Since both add to 100%, we get horses as 80%.

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