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Position of a Falling Body with Linear Resistance
For a body released from rest:
$$x=\frac{mg}{k}t-\frac{m^2g}{k^2}\left(1-e^{-kt/m}\right)$$
Usage
- Gives displacement as a function of time under linear resistance.
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Position of a Falling Body with Linear Resistance
For a body released from rest:
$$x=\frac{mg}{k}t-\frac{m^2g}{k^2}\left(1-e^{-kt/m}\right)$$
Usage
- Gives displacement as a function of time under linear resistance.
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