Separable Equation with Initial Condition

Rarely Tested

Separable Equation with Initial Condition

For:

$$\frac{dy}{dx}=f(x)g(y),\quad y(x_0)=y_0$$

the solution can be written as:

$$\int_{y_0}^{y}\frac{du}{g(u)}=\int_{x_0}^{x}f(t)\,dt$$

Usage

- Avoids explicitly calculating the arbitrary constant and is useful for initial-value problems.

Question 1

Let $$y:(-\infty,\infty)\to(0,\infty)$$ be the solution of the differential equation

$$\dfrac{dy}{dx}=\dfrac{e^{5x}y^3+y^3}{e^x+e^x y^4},$$

satisfying $$y(0)=\dfrac{1}{\sqrt{2}}$$. Then the value of $$y(\log_e 2)$$ is

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