Locus of a Point Equidistant from Two Fixed Points
## Formula
For fixed points $$A(x_1,y_1)$$ and $$B(x_2,y_2)$$, if:
$$PA=PB$$
then:
$$(x-x_1)^2+(y-y_1)^2=(x-x_2)^2+(y-y_2)^2$$
## Usage
- Used to derive the perpendicular bisector of the segment joining two fixed points.