Locus of a Point Equidistant from Two Fixed Points

Rarely Tested

Locus of a Point Equidistant from Two Fixed Points

## Formula

For fixed points $$A(x_1,y_1)$$ and $$B(x_2,y_2)$$, if:

$$PA=PB$$

then:

$$(x-x_1)^2+(y-y_1)^2=(x-x_2)^2+(y-y_2)^2$$

## Usage

- Used to derive the perpendicular bisector of the segment joining two fixed points.

No related questions available for this formula yet.

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