Question 57

A bag contains 8 red and 6 blue balls. If 5 balls are drawn at random, what is the probability that 3 of them are red and 2 are blue?

Solution

5 balls are drawn at random, hence the probability that 3 of them are red and 2 are blue = $$\dfrac{8c3*6c2}{14c5}$$ = $$\dfrac{60}{143}$$

Hence, option D is the correct answer.

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