Question 32
There are two buildings, one on each bank of a river, opposite to each other. From the top of one building - 60 m high, the angles of depression of the top and the foot of the other building are 30° and 60° respectively. What is the height of the other building?
Solution
Width of the river = tan 30 * 60 = 20$\sqrt3$
Now Tan 30 = (60-x)/(20$\sqrt3$)
Solving we get x = 40m
Thus, the height of the building = 40m
Hence, option C is the correct answer.
The given situation is as shown:-
Width of the river = tan 30 * 60 = 20$\sqrt3$
Now Tan 30 = (60-x)/(20$\sqrt3$)
Solving we get x = 40m
Thus, the height of the building = 40m
Hence, option C is the correct answer.
Video Solution
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