A hemispherical bowl is filled with hot water to the brim. The contents of the bowl are transferred into a cylindrical vessel whose radius is 50% more than its height. If diameter of the bowl is the same as that of the vessel, the volume of the hot water in the cylindrical vessel is

The volume of the hot water in the hemispherical bowl = $$\frac{2*\pi*r^3}{3}$$
Given that Radius of the hemispherical bowl and that of the cylindrical vessel is the same.
Also, radius is 50% more than its height.
Thus, h = $$\frac{2r}{3}$$
Thus, the volume of the cylindrical vessel = $$\frac{2*\pi*r^3}{3}$$
Hence, the volume of the hot water in the cylindrical vessel is 100% of the cylindrical vessel.
Hence, option C is the correct answer.