SRCC GBO Sample Paper 2026

Rahul scored 25% of runs and increased by 20% and so total runs scored by him is (25/100)*(1.2)*2600=780 runs
Archer scored 15% of runs and increased by 10% and so total runs scored in the next
season =(15/100)*(1.1)*2600
=429 runs
Sum=780+429
=1209

From the given graphs, we can obtain the values as,

                                                 Boys and Girls

                                                         Boys

                                                            Girls

The ratio of the number of boys in pre-primary government schools to the number of girls in secondary schools is,

50 : 350 = 1 : 7

The correct answer is option B.

From the given graphs, we can obtain the values as,

                                                 Boys and Girls

                                                        Boys

                                                           Girls

Percentage = $$\dfrac{700}{4150}\ \times\ 100$$ = 16.86%

The correct answer is option B.

From the given graphs, we can obtain the values as,

                                            Boys and Girls

                                                       Boys

                                                        Girls

The ratio of private primary girls to private primary boys is 300 : 600 = 1 : 2

Option A:

Government primary girls : Private senior secondary boys = 250 : 100 = 5 : 2

Option B:

Private secondary girls : Private secondary boys = 50 : 150 = 1 : 3

Option C:

Government primary girls : Private upper primary boys = 250 : 150 = 5 : 3

Option D:

Government pre-primary girls : Private senior secondary boys = 50 : 100 = 1 : 2

The correct answer is option D.

From the given graphs, we can obtain the values as,

                                                Boys and Girls

                                                        Boys

                                                          Girls

Percentage = $$\dfrac{2300\ -\ 1850}{1850}\ \times\ 100$$ = 24.32%

The correct answer is option A.

We are given that the ratio of number of Apple products to Samsung products 2:7. Assume the number of Apple products = 2x and  number of Samsung products = 7x.

Similarly, we are given that the ratio of number of Xiaomi products to Vivo products is 5:11 Assume the number of Xiaomi products = 5y and number of Vivo products = 11y.

We are also told that the ratio of number of Samsung products to Vivo products is 5:9.

The ratio of  number of Samsung products to Vivo products = 7x:11y

We are told that 7x:11y = 5:9

For this to be true, x has to be a multiple of both 11 and 5. Similarly y has to be multiple of 7 and 9.

Since we are asked for the minimum value, x = 11*5 = 55 and y = 7*9 = 63

number of Apple products = 2x = 110

number of Samsung products = 7x = 385

number of Xiaomi products = 5y = 315

number of Vivo products = 11y = 693

Sum = 1503

The set A consists of integers between 1 and 100 that are multiples of 6. 

The set B consists of integers between 1 and 200 that are multiples of 8. 

(A$$\cap$$B) is the set of multiples of LCM(6, 8) = 24, between 1 to 100.

(A$$\cap$$B) = {24, 48, 72, 96}

The size of B is 200/8 = 25.

So, the size of C = 25-4 = 21.

The total surface area of the bigger cone and the figure formed will be the same as the area in which the smaller cone closes on the base, the same as the area at the top of the other part. So, the total surface area of the figure can be calculated as,

Slant height l  =  $$\sqrt{\ r^2\ +\ h^2\ }\ =\ \sqrt{\ 14^2\ +\ 48^2}\ =\ \sqrt{\ 2500}\ =\ 50\ $$

Total surface area = $$\pi\ r\left(r\ +\ l\right)$$ = $$\dfrac{22}{7}\ \times\ 14\left(50\ +\ 14\right)\ $$ = $$22\ \times\ 2\ \times\ 64\ $$ = 2816

The correct answer is option D.

Rohit can finish 75% of a task in 24 days

Shyam can complete 62.5% of the same task in 10 days.

We know Rohit and Shyam have worked together for 8 days.

Therefore, work done by Rohit in 8 days =?

75% of a task in 24 days,

25% of a task in 8 days.

Thus, Rohit completes 25% of the task in 8 days.

Similarly, Shyam will complete work in 8 days =?

62.5% of the same task in 10 days.

6.25% of tasks in 1 day.

Therefore, 50% of tasks in 8 days.

Therefore, Rohit and Shyam complete 25%+50% = 75% of the task in 8 days.

Mohan completes the remaining task in 5 days

Thus, Mohan completes 25% of the task in 5 days.

Mohan completes 5% of tasks in 1 day.

Therefore, he will take 16 days to complete the 80% of the task.

We are told that  B took 50% more time than C to finish the race, and B also took 25% more time than A.

So, $$1.5*T_c = T_b$$, $$ T_b=1.25T_a$$.

From this $$T_a = \frac{6}{5}T_c$$

Let's find the speeds of all three. $$S_c =  \frac{1000}{T_c}$$, $$S_b = \frac{1000}{T_b} = \frac{1000}{1.5*T_c}$$, $$S_a=\frac{1000}{T_a}=\frac{1000}{\frac{6}{5}*T_c}=\frac{\left(5\cdot1000\right)}{6\cdot T_c}$$

The ratio of the speeds of A, B, C will be $$\frac{5}{6}:\frac{1}{1.5}:1=\frac{5}{6}:\frac{2}{3}:1=5:4:6$$.

The distance between the meeting points of A, C and B, C. 

The ratio of the speeds of A and C is 5:6. Time taken for them to meet = $$\frac{1100}{5x+6x}=\frac{1100}{11x}=\frac{100}{x}$$

 Distance C travelled = $$6x\cdot\frac{100}{x}$$ = 600m.

The ratio of the speeds of B and C is 4:6. Time taken for them to meet = $$\frac{1100}{4x+6x}=\frac{1100}{10x}=\frac{110}{x}$$

Distance C travelled = $$6x\cdot\frac{110}{x}$$ = 660m.

So, the distance between two meeting points = 60m