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Two circles of equal radius 12cm, C1 and C2, are in such a way that they are not intersecting each other. A tangent is drawn to C1 from the intersectionΒ point ofΒ the line joining the centres of both circles, and circle C2. If the length of the tangent is given as 16cm, then what isΒ the distance between the centres of the circles?
As shown in the figure above, we must calculate the length of BD. We are given theΒ length of ACΒ as 16 and AB as 12. The length BC can be calculated as,
$$AC^2\ +\ AB^2\ =\ BC^2$$
$$BC\ =\ \sqrt{\ AC^2\ +\ AB^2}$$
$$BC\ =\ \sqrt{\ 12^2\ +\ 16^{\ 2}}\ =\ \sqrt{\ 144+256}\ =\ 20$$
The length BD =Β BC + CD = 20 + 12 = 32 cm
The correct answer is optionΒ D.
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