Study the following information carefully to answer the given questions.
A, B, C, D, E, and F are arranged around a circular table.
* C and D are placed such that they are equidistant to A. They are also placed at an equal distance to B.
* E is placed second to the left of A.
* Only one pair of adjacent alphabets are seated opposite to each other.
Numbers from 1 to 6 are assigned starting from A in the clockwise direction.
Solution
According to the first statement, A and B must be opposite each other for C and D to be equivalent to both A and B.
Since A and B are already adjacent to each other, the other pairs must not be adjacent to each other. It is also given that E is second to the left of A , and F has to be second to the right of A.
There is only one possible arrangement for C and D that satisfies the condition of adjacent letters not being opposite each other. This can be given by the figure below,
The value of C * E * F = 6 * 3 * 5 = $$2\ \times\ 3^2\ \times\ \ 5$$The number of factors = (1 + 1) * (2 + 1) * (1 + 1) = 12
Hence, the correct answer is option C.
