Circle Having a Given Line as Diameter

Circle Having a Given Line as Diameter

If a line segment has endpoints $$A(x_1,y_1)$$ and $$B(x_2,y_2)$$, the circle having $$AB$$ as diameter is:

$$(x-x_1)(x-x_2)+(y-y_1)(y-y_2)=0$$

Usage

- Used to convert a fixed line segment into its corresponding diameter-circle locus.