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$$ \int \frac{1}{\sqrt{1-x^2}} \, dx = \sin^{-1} x + C $$
$$ \int \frac{1}{1+x^2} \, dx = \tan^{-1} x + C $$
$$ \int \frac{1}{|x|\sqrt{x^2-1}} \, dx = \sec^{-1} x + C $$
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