The ratio of ‘metal 1’ and ‘metal 2’ in alloy ‘A’ is 3 :4. In alloy ‘B’ same metals are mixed in the ratio 5:8. If 26 kg of alloy ‘B’ and 14 kg of alloy ‘A’ are mixed then find out the ratio of ‘metal 1’ and ‘metal 2’ in the new alloy.

The ratio of ‘metal 1’ and ‘metal 2’ in alloy ‘A’ is 3 :4.Therefore, we can say that 14 kg of alloy 'A' will contain $$\dfrac{3}{7} 14$$ = 6 kg of 'metal 1' and $$\dfrac{4}{7} 14$$ = 8 kg of 'metal 2'.

The ratio of ‘metal 1’ and ‘metal 2’ in alloy ‘B’ is 5 :8.Therefore, we can say that 26 kg of alloy 'B' will contain $$\dfrac{5}{13} 26$$ = 10 kg of 'metal 1' and $$\dfrac{8}{13} 26$$ = 16 kg of 'metal 2'.

Hence, total weight of 'metal 1' in the new alloy = 6 + 10 = 16 kg
Total weight of 'metal 2' in the new alloy = 8 + 16 = 24 kg

Therefore, the ratio of ‘metal 1’ and ‘metal 2’ in the new alloy. = 16 : 24 = 2 :3. Hence, option C is the correct answer.