a, b and c are the three digits of a number abc. abc is a multiple of 3. Find (a + b + C).
A. a = 3, b = 4.
B. C is an odd number.

If $$abc$$ is a multiple of 3, then $$(a+b+c)$$ will also be multiple of 3.

(A) : $$a=3$$ and $$b=4$$

=> $$3+4+c=3k$$, where $$k$$ is a natural number.

=> Possible values of $$c=2,5,8$$

Thus, statement A alone is not sufficient.

(B) : If C is odd, there can be multiple values of the number, thus statement B alone is insufficient.

By combining above statements together, we get the number as 345

$$\therefore$$ Both statements together are sufficient.

=> Ans - (C)