SRCC GBO Sample Paper 2026

Highest profit per car = $$\frac{\text{Total}\ \text{profit}}{\text{Market share}}$$

Profit is positive for TATA, Hyundai, BYD. Let 100x be the total number of cars sold.

TATA's profit per car = 7.5/x

Hyundai's profit per car = 2/x

BYD's profit per car = 3.75/x

So, this is highest for TATA.

Only Tata, Hyundai and BYD are making a profit. 

Profit % = Profit / Expenditure * 100% 

TATA Profit % = 510/ 510 *100%  = 100%

Hyundai = 10/80 *100% = 12.5%

BYD = 15k/120k *100% = 12.5%

Hence, answer is TATA.

Profits are not positive for MG and M&M. So, the answer is two.

Profit percentage = $$\dfrac{510}{510}\ \times\ 100\ =100$$

So, the profit is 100%.

If the team total score is 400, then the runs scored by KL is given by $$\dfrac{53}{100}\ \times\ 400$$ = 212.

Runs scored by KL through boundaries = 23 * 4 = 92

Runs scored by KL without boundaries = 212 - 92 = 120

Percentage of runs scored by KL without boundaries = $$\dfrac{120}{212}\ \times\ 100$$ = $$56.6\%$$

The correct answer is option C.

We are given the score of WASHI as 36.

The percentage of runs scored by WASHI is 9%

$$\dfrac{9}{100}\ \times\ total\ score\ =\ 36$$

$$\ total\ score\ = 400$$

Number of boundaries scored by the whole team = 23 + 6 + 1 + 2 + 5 + 5 = 42

Score attained through boundaries = 42 * 4 = 168

The score without boundaries = 400 - 168 = 232

The correct answer is option A. 

Runs scored by the players through boundaries are,

KL - 23 * 4 = 92

YASH - 6 * 4 = 24

GILL - 1 * 4 = 4

VIRAT - 2 * 4 = 8

PANT - 0 * 4 = 0

ROHIT - 0 * 4 = 0

WASHI - 5 * 4 = 20

NITISH - 5 * 4 = 20

We know that for a particular player, the runs scored must be greater than or equal to the runs he scored through boundaries. We also know that the combined runs of all the players together must be a multiple of 100 for individual player runs to be integers.

The minimum score cannot be 100 or 200 because, in the case of 100, runs scored by KL becomes $$\dfrac{53}{100}\ \times\ 100\ =\ 53$$, but we already know that KL scored 92 runs through boundaries. So, 100 does not satisfy the given conditions. 

In the case of 200, the runs scored by WASHI can be calculated as $$\dfrac{9}{100}\ \times\ 200\ =\ 18$$, but we already know that he scored 20 runs through boundaries. So, 200 does not satisfy the given conditions.

So, the minimum score possible is 300 to satisfy all the given conditions.

The number of factors of 300 can be calculated as,

$$300\ =\ 2^2\ \times\ 3\ \times\ 5^2$$

Number of factors = (2 + 1) * (1 + 1) * (2 + 1) = 3 * 2 * 3 = 18

The correct answer is option D.

Given that the score of GILL is 6, the total number of runs scored can be calculated as,

$$\dfrac{2}{100}\ \times\ total\ =\ 6$$

$$\ total\ =\ 300$$

Runs scored by YASH can be calculated as,

$$\dfrac{15}{100}\ \times\ 300\ =\ 45$$

Runs scored by YASH through boundaries = 6 * 4 = 24

The percentage of runs scored through boundaries can be calculated as,

$$\dfrac{24}{45}\ \times\ 100\ =\ 53.334$$

The correct answer is option C.

Average runs per match of South Africa in 2011 = $$\dfrac{1200}{8}$$ = 150

Average runs per match of Australia in 2007 = $$\dfrac{1350}{9}$$ = 150

150:150 = 1:1

We have to find the highest among $$\frac{4800}{34}$$, $$\frac{4300}{31}$$, $$\frac{5450}{39}$$, $$\frac{4150}{33}$$.

The highest is $$\frac{4800}{34}$$. Hence, India is the answer.