SNAP 2023 Question Paper

Let the cost price be 100, so he sold the t-shirt for 120
But 120 was after 25% discount
So marked price = 120/.75= 160
So he marked the t-shirt 60% above the cost price.

Speed of local train = 36*5/18 m/s =10 m/s
So distance covered by it in 30 mins = 10 * 30 *60 = 18000 m
Speed of Chennai express = 72*5/18 m/s =20 m/s
Since both travel in same direction, relative speed = 20 -10 = 10m/s
So, time required to overtake = distance / relative speed = 18000 /10 = 1800 sec
So C is the right choice.

Let the speed of the boat be 3x and the speed of the stream be x.
Then it is given that
20/(3x-x) = 4
=> 2x = 5
=> x = 2.5
=> Speed of the boat is 7.5 km/hr and speed of the stream is 2.5 km/hr
Now while going downstream, the effective speed would be 7.5 + 2.5 = 10 km/hr
Hence the required time = 20/10 = 2 hours.

We know that a, b, c and d are distinct even natural numbers less than 10. Therefore, they must be 2, 4, 6 and 8.
Product of the 4 numbers =$$ 2*4*6*8$$ = $$2*2*2*2*3*2*2*2$$ = $$2^7 * 3$$

Therefore, $$2^7 = 128$$ is the highest power of $$2$$ that will definitely divide the product. Hence, option C is the right answer.

$$k^4 + \frac{1}{k^4} +2 = 49 => (k^2+\frac{1}{k^2})^2 = 7^2 => k^2 +\frac{1}{k^2} = 7$$.

Similarly, $$k^2 + \frac{1}{k^2} + 2 = 9 => k+\frac{1}{k} = 3.$$

$$(k+1/k)^3 = k^3 + 1/k^3 + 3(k+1/k)=> k^3 +1/k^3 = 27 - 3*3 = 18.$$

Here n(S) = 100 (As mentioned in the problem)
Favorable cases to get the square cards = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100}
n(E) = 10
Probability = n(E)/n(S) =10/100=1/10

Probability of 1st ball being Non-red => $$ \frac{7}{12} $$
Probability of 2nd ball being Non-red => $$ \frac{6}{11} $$
Since, both the balls being non-red => $$ \frac{6}{11} \times \frac{7}{12} $$ => $$ \frac{7}{22} $$
Option D is correct

N.o of two digit numbers divisible by 5 = 10 , 15 ,20......95

N.o of two digit numbers divisible by 7=14 , 21 , 28.....98\

N.o of two digit numbers divisible by 35= 35, 70

Using $$S_{n\ }=\ \frac{n}{2}\left(2a+\left(n-1\right)d\right)$$

We can find out that the sum numbers divisible by 5 is 945

And sum of numbers divisible by 7 is 728

We need to subtract the numbers divisible by both 5 and 7 which is equal to 35+70=105

So total = 945+728-105= 1568

Let the number of people who read exactly one newspaper be ‘a’, the number of people who read exactly two newspapers be ‘b’ and the number of people who read exactly three newspapers be ‘c’.
So, a + b + c = 100%
a + 2b + 3c >= 70% + 75% + 80% = 225%
=> b + 2c >= 125
To find the minimum percentage of people who read all three newspapers, we have to minimize ‘c’. So, we have to maximize ‘b’.

Let a = 0 => b+c = 100 and b+2c >= 125
=> c >= 25
So, the minimum value of ‘c’ is 25. In this case, b = 75 and a = 0
So, at least 25% of the people in the neighbourhood read all the three newspapers.

Volume of one sphere = $$\frac{4}{3}\pi R^3$$ = $$36\pi$$
Volume of five spheres = $$180\pi $$
Therefore, volume of cylinder = $$180\pi $$
Radius of cylinder = 3 cm
$$\pi R^2H$$ = $$180\pi $$
H = 20 cm
Hence, option B is the correct answer.