Question 58
A and B can complete a work in 40/3 days.B and C can complete the same work in 80/3 days.A and C can complete the work in 16 days.How many days can A,B and C together can complete the work ?
Solution
Given (1/a)+(1/b)=3/40
(1/b)+(1/c)=3/80
(1/c)+(1/a)=1/16
(1/a)-(1/c)=3/80
Adding both the above equations we get
(2/a)=1/10
a=20 days
Substituting in above equation we get b=40 days
c=80 days
Three combinedly can do the total work in x days
(1/20)+(1/40)+(1/80)=1/x
x=80/7 days
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