Question 51
If (3,2) is the centroid of a triangle of vertices A(x,1), B(4,6) and C(-1, y) then find the value of (x+y) ?
Solution
Centroid = $$(\frac{x_{1}+x_{2}+x_{3}}{3} , \frac{y_{1}+y_{2}+y_{3}}{3})$$
(3, 2) = $$(\frac{x+4-1}{3} , \frac{1+6+y}{3})$$
$$\frac{x+3}{3}$$ = 3 and $$\frac{7+y}{3}$$ = 2
x+3 = 9 and 7+y = 6
x = 6 and y = -1
x+y = 6-1 = 5
So the answer is option C.
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