Rarely Tested

Sum of Products $$k(k-1)$$

## Formula

$$\sum_{k=1}^{n}k(k-1)=\frac{n(n+1)(n-1)}3$$

Equivalently:

$$\sum_{k=1}^{n}k(k-1)=2\sum_{k=1}^{n}\binom{k}{2}$$

## Usage

- Used to simplify polynomial summations involving consecutive products.

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