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Sum of First $$n$$ Even Numbers
## Formula
$$2+4+6+\cdots+2n=n(n+1)$$
Therefore:
$$\sum_{k=1}^{n}2k=n(n+1)$$
## Usage
- Used in summation problems involving consecutive even numbers.
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Sum of First $$n$$ Even Numbers
## Formula
$$2+4+6+\cdots+2n=n(n+1)$$
Therefore:
$$\sum_{k=1}^{n}2k=n(n+1)$$
## Usage
- Used in summation problems involving consecutive even numbers.
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