Amphoteric Nature of Aluminum

Rarely Tested
$$ 2Al + 2NaOH + 6H_2O \rightarrow 2Na[Al(OH)_4] + 3H_2 $$
$$ Al_2O_3 + 2NaOH \rightarrow 2NaAlO_2 + H_2O $$

Aluminum reacts with NaOH to form sodium tetrahydroxoaluminate. Aluminum oxide dissolves in NaOH to form sodium metaaluminate.

No related questions available for this formula yet.

Go back to topics

Join CAT 2026 course by 5-Time CAT 100%iler

Start your IIM journey with the right preparation and crack CAT 2026.

Enroll Now