Question 9

# The sum of three consecutive even numbers is 28 more than the average of these three numbers. Then the smallest of these three numbers is

Solution

Given that, Sum of the three consecutive even numbers is 28 more than the average of those three numbers

Lets consider the three numbers as 2n, 2n+2,2n+4

Therefore, $$2n+2n+2+2n+4$$ = $$\frac{2n+2n+2+2n+4}{3}+28$$

=> $$6n+6$$ = $$2n+2+28$$

=> 4n=24 => n=6

Therefore, smallest number 2n= 2(6)=12