Find the largest 5 digit number which when divided by 4, 9, and 11 leaves the same but largest remainder for all the three numbers ?

The largest remainder we can get, = smallest of {largest remainder of '4', the largest remainder of '11', the largest remainder of '9'}

= smallest of {3,10,8} = 3.

The number which gives the remainder '3', when divided by 4,9& 11, will be of the form = L.C.M of (4,9&11) x n + 3.

L.C.M of (4,9&11) = 396.

The number which gives the remainder '3', when divided by 4,9& 11, will be of the form = 396n+3.

The largest 5-digit number of the form, 396n+3 = 396 x 252 + 3

=99792+3=99795.

Option (D) is correct.