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Question 76
$$\triangle ABC$$ is similar to $$\triangle DEF$$. If area of $$\triangle ABC$$ is 9 sq.cm. and area of $$\triangle DEF$$ is 16 sq.cm. and BC = 2.1 cm. Then the length of EF will be
Solution
if triangle are similar thenÂ
$$\frac{area of \triangle ABC}{area of\triangle DEF}$$ = $$\frac{BC^2}{EF^2}$$Â
$$\frac{9}{16}$$Â = $$\frac{BC^2}{EF^2}$$Â
$$\frac{2.1}{EF}$$Â = $$\frac{3}{4}$$
EF = 2.8 cm
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