If the number of students who were present in the Physics examination from school A is 250% of the difference of the number of the students who were present in Physics and Biology examination, from school K, then what is the ratio of the number of students who were present from school L to number of students who were present in Physics examination from school A?

Total number of students in K= $$\frac{83300}{0.35}=238000.$$

Students present in K= $$238000\times0.65=154700.$$

So, difference in Present in Physics and Biology in K= $$154700\times\left(0.68-0.32\right)=55692.$$

So, Present in physics in A= $$55692\times2.5=139230.$$

Total students present in L=  $$\frac{101520}{0.40}\times0.6=152280\ .$$

So, required ratio = $$\frac{152280}{139230}=\frac{1692}{1547}\ .$$

B is correct choice.