The portion of a ditch 48 m long, 16.5 m wide and 4 m deep that can be filled with stones and earth available during excavation of a tunnel, cylindrical in shape, of a diameter 4 m and length S6 mis
Volume of the earth dugout as a tunnel
= pi*r^2*h=(22)/7×2×2×56=704m^3
Volume of the ditch = 48×(33)/2×4
= 24 X 33 X 4 = 3168
Therefore, Part required = 704/3168=29
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