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With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 30 km/hr, it is late by 36 minutes. The total distance travelled by train is :
Let us consider with average speed of 40 km/hr, train reached its destination in time t hrs
with average speed of 30 km/hr, it takes t +$$\frac{36}{60}$$ hrs
Distance will be same in both the cases
40t = 30t + 18
10t = 18
t = $$\frac{18}{10}$$
Distance = 40t = 40$$\times\ \frac{18}{10}$$ = 72 km
Answer is option A.
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