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At a dinner party, every two guests used a dish of rice between them. Every three guests used a dish of daal and every four used a dish of meat between them. There were altogether 65 dishes. How many guests were present?
Let the total number of guests beΒ $$x$$
Number of rice bowls = $$\frac{x}{2}$$
Number of bowls of daal = $$\frac{x}{3}$$
Number of bowls ofΒ meat = $$\frac{x}{4}$$
=> $$\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=65$$
=> $$\frac{6x+4x+3x}{12}=65$$
=> $$\frac{13x}{12}=65$$
=> $$x=5\times12=60$$
$$\therefore$$Β 60 guests were present.
=> Ans - (C)
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