If $$x$$ is an integer, then what is the value of $$x^2$$ ?

A. $$\left(\frac{1}{5}\right) < \left(\frac{1}{(x + 1)}\right) < \left(\frac{1}{2}\right)$$

B. $$(x - 3) (x- 4) = 0$$

A) : $$\left(\frac{1}{5}\right) < \left(\frac{1}{(x + 1)}\right) < \left(\frac{1}{2}\right)$$

=> $$2<(x+1)<5$$

=> $$1<x<4$$

Thus, possible values of $$x$$ are : 2, 3 and since there is not a unique value, hence this statement alone is insufficient.

B) : $$(x - 3) (x- 4) = 0$$

=> $$x=3,4$$

Similarly, this statement alone is also not sufficient. But by combining both statements, we get : $$x=3$$ and $$x^2=9$$

=> Ans - (C)