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In a certain town, 40% of people have brown hair, 30% of people have brown eyes and 12% have both brown hair and brown eyes.
How many people in town have neither brown hair nor brown eyes ?
Let total number of people in the town = $$100x$$
People who have both brown hair and eyes = $$b=12x$$
=> People who have brown hair = $$a+b=40x$$
=> $$a=28x$$
Similarly, $$c=18x$$
$$\therefore$$ People who have neither brown hair nor brown eyes = $$100x-(12x+18x+28x)=42\%$$
=> Ans - (D)
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