CMAT 2020 Question 4

Question 4

In a certain town, 40% of people have brown hair, 30% of people have brown eyes and 12% have both brown hair and brown eyes.
How many people in town have neither brown hair nor brown eyes ?

Solution

Let total number of people in the town = $$100x$$

People who have both brown hair and eyes = $$b=12x$$

=> People who have brown hair = $$a+b=40x$$

=> $$a=28x$$

Similarly, $$c=18x$$

$$\therefore$$ People who have neither brown hair nor brown eyes = $$100x-(12x+18x+28x)=42\%$$

=> Ans - (D)


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