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Find the smallest number by which 2400 should be divided to make it a perfect cube.
220
385
260
300
Prime factorization of :
$$2400=(2)^5\times(3)\times(5)^2$$
Now, to make it a perfect cube, we need to make the powers multiple of 3, and thus we need to divide it by = $$(2)^2\times3\times(5)^2=300$$
=> Ans - (D)
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