If A = 0.abcabc ......, then by what number A should be multiplied so as to get an integeral value?
$$A=0.abcabc......$$
So, $$1000A=\left(abc+0.abc......\right)$$
or, $$1000A=\left(abc+A\right).$$
or, $$999A=\left(abc\right).$$
or, $$A=\frac{abc}{999}.$$
So, To get an integral value ,we should multiply A by a number which is a multiple of 999.
From choice 2997 and 1998 both are multiple of 999.
D is correct choice.
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