In a laboratory, two bottles contain mixture of acid and water in the ratio 2 : 5 in the first bottle and 7 : 3 in the second. The ratio in which the contents of these two bottles be mixed such that the new mixture has acid and water in the ratio 2:3 is
ratio of acid and water in the first bottle =Â 2 : 5
acid in the first bottle = $$ \frac{2}{7} $$
ratio of acid and water in the second bottle =Â 7 : 3
acid in the second bottle = $$ \frac{7}{10} $$
ratio of acid and water in the new mixture = 2 : 3
acid of new mixture = $$ \frac{2}{5} $$
using alligation method
ratio in which the contents of these two bottles be mixed = $$ \frac{3}{10} : \frac{4}{35} $$
                                            = 21 : 8
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