ABCDE play a game of cards. ‘A’ tells ‘B’ that if ‘B’ gives him five cards ‘A’ will have as many cards as ‘E’ has. However if A gives five cards to ‘B’ then ‘B’ will have as many cards as ‘D’. A and B together has 20 cards more than what D and E have together. B has four cards more than what C has and total number of cards are 201. How many cards B have?

Let 'a' be the number of cards with B. If A gives five cards to ‘B’ then ‘B’ will have as many cards as ‘D’. 

Hence, the number of cards with D = 'a+5'.

B has four cards more than what C has. Hence, the number of cards with c = 'a-4'.

Let us assume that number of cards with A = 'x'. It is given that if ‘B’ gives 'A' five cards the A will have as many cards as ‘E’ has.

Hence, the number of cards with 'E' = x+5.

It is also given that A and B together has 20 cards more than what D and E have together.

Hence, (a+x) - (a+5+x+5) = 20.

Data given in the question contradicts with th information. Hence, this question can't be answer. Therefore, option D is the correct answer.