Question 17

If $$\frac{(a + b)}{c} = \frac{6}{5}$$ and $$\frac{(b + c)}{a} = \frac{9}{2}$$, then what is the value of $$\frac{(a + c)}{b}$$?

Solution

$$\frac{(a + b)}{c} = \frac{6}{5}$$
5a+5b=6c
$$\frac{(b + c)}{a} = \frac{9}{2}$$
2b+2c=9a
9a-2b=2c
27a-6b=6c
5a+5b=6c
27a-6b=5a+5b
22a=11b
b=2a
4a+2c=9a
2c=5a
c=(5/2)a
$$\frac{(a + c)}{b}$$
=((a+(5/2)a))/2a
=7a/4a
=7/4

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SSC CGL Tier-2-17-February-2018 Maths

If $$\frac{(a + b)}{c} = \frac{6}{5}$$ and $$\frac{(b + c)}{a} = \frac{9}{2}$$, then what is the value of $$\frac{(a + c)}{b}$$?

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