A man, from the foot of the building P, walks towards the building Q. After walking for 2 mts, he
finds that buildings P and Q makean angle of elevation of $$60^{0}$$ and $$30^{0}$$ respectively. If building Q is
1.5 mts high, find the distance between the tops of both buildings P and Q.

A

5 mts

B

4 mts

C

$$(\sqrt[2]{3}-1.5)mts$$

D

$$(2-1.5\sqrt{3})mts$$