Question 157

Ten points are marked on a straight line and eleven points are marked on another straight line. How many triangles can be constructed with vertices from among the above points?

Solution

A triangle can be formed by taking any two points of a straight line and third point on the second straight line

=> Number of ways = $$(C_2^{10}\times11)+(C_2^{11}\times10)$$

= $$495+550=1045$$

=> Ans - (C)

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