In his wardrobe, Timothy has 3 trousers. One of them is black, the second blue, and the third brown. In his wardrobe, he also has 4 shirts. One of them is black and the other 3 are white. He opens his wardrobe in the dark and picks out one shirt-trouser pair, without examining the colour. What is the likelihood that neither the shirt nor the trouser is black?
Probability that trouser is not black = $$1-\frac{1}{3}=\frac{2}{3}$$
Probability that shirt is not black = $$1-\frac{1}{4}=\frac{3}{4}$$
$$\therefore$$ Required probability = $$\frac{2}{3}\times\frac{3}{4} =\frac{1}{2}$$
=> Ans - (D)
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