IIFT 2013 Question Paper

Question 128

Capacity of tap Y is 60% more than that of X. If both the taps are opened simultaneously, they take 40 hours to fill the rank. The time taken by Y alone to fill the tank is


We are given that 1.6Y = X
Thus, $$\dfrac{1}{1.6Y}+\dfrac{1}{Y} = \dfrac{1}{40}$$
=> $$104/1.6 = Y$$
Thus, Y = 65 hours.
Hence, option B is the correct answer.

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