A man takes 4 hours 20 minutes in walking to a certain place and riding back. If he walks on both sides, he loses 1 hour. The time he would take by riding both ways is

Let $$T_w$$ be the time taken to walk one way and $$T_r$$ be the time taken to ride one way.

So, $$T_w+T_r=$$ $$4$$ hours $$20$$ minutes

or, $$T_w+T_r=260$$ ---->(1)

Now, it is given, if he walks on both sides, he loses 1 hour

so, $$2T_w=260+60=320$$ ---->(2)

Multiplying equation (1) by 2 and subtracting equation (2) from it,

$$2T_r=520-320=200$$

So, time taken in riding both ways = 200 minutes = 3 hours and 20 minutes.

So, correct answer is option (C).