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Question 113
Let PQRSTU be a regular hexagon. The ratio of the area of the triangle PRT to that of the hexagon PQRSTU is
Solution
It's given that PQRSTU is a regular hexagon and O is the center of the hexagon.
If we fold $$\triangle$$TSR ,$$\triangle$$PQR ,$$\triangle$$TUP along lines TR, PR, PT respectively then vertices S,Q,U will overlap each other exactly at center of the hexagon.
Hence we can say that Area of hexagon PQRSTU = 2($$\triangle$$PRT)
So Area of $$\triangle$$PRT = 0.5(Area of hexagon PQRSTU)
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