What is the probability of getting a ‘nine’ or ‘ten’ on a single throw of two dice?

Probability = Expected number of outcomes/ Total number of outcomes.

Total number of outcomes we get in a single throw of two dice = $$6\times 6$$ = 36.

Possible cases of getting 'nine' in a single throw of two dice:

                  dice 1           dice 2

                  three             six..................(1)

                  six                three................(2)

                  four              five..................(3)

                  five              four...................(4)

So, total of 4 cases.

Possible cases of getting 'ten' in a single throw of two dice:

                dice 1            dice 2

                four                six.....................(1)

                 six                 four....................(2)

                five                 five....................(3)

So, total of 3 cases.

Expected number of outcomes = Total possible cases of getting 'nine' or 'ten'  in a single throw of two dice = 4 + 3 = 7 .

So, Probability = $$\frac {7} {36}$$