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If the unit digit of $$(433 \times 456 \times 43N)$$ is $$(N + 2)$$, then what is the value of $$N$$?
If we multiply 433 and 456 then we will get 8 as unit digit .
But when 433 and 456 multiply together with 43N then the unit digit appears as 8N .
So,Unit digit of $$8N=N+2$$ .
It is possible only when N=6 .
So, D is correct choice.
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