If $$N = (12345)^2 + 12345 +12346$$, then what is the value of $$\surd N$$ ?
$$N=(12345)^2+12345+12346=12345^2+12345+12345+1=12345^2+2\times12345\times1+1^2$$
So, $$N=(12345+1)^2$$
So, $$\sqrt{N}=12346\ .$$
A is correct choice.
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