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NTA JEE Main 8th April 2019 Shift 2 - Chemistry

For the following questions answer them individually

0.27 g of a long chain fatty acid was dissolved in 100 cm$$^3$$ of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer?
[Density of fatty acid = 0.9 g cm$$^{-3}$$; $$\pi = 3$$]

If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength $$\lambda$$, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be: (Assume kinetic energy of ejected photoelectron to be very high in comparison to work function)

5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If $$C_V = 28$$ J K$$^{-1}$$, calculate $$\Delta U$$ and $$\Delta pV$$ for the process. (R = 8.0 J K$$^{-1}$$ mol$$^{-1}$$)

For the following reaction, equilibrium constants are given:
$$S(s) + O_2(g) \rightleftharpoons SO_2(g); \quad K_1 = 10^{52}$$
$$2S(s) + 3O_2(g) \rightleftharpoons 2SO_3(g); \quad K_2 = 10^{129}$$
The equilibrium constant for the reaction, $$2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$$ is:

Calculate the standard cell potential (in V) of the cell in which the following reaction takes place:
Fe$$^{2+}$$(aq) + Ag$$^+$$(aq) $$\rightarrow$$ Fe$$^{3+}$$(aq) + Ag(s)
Given that $$E^{0}_{Ag^+/Ag} = x$$ V, $$E^{0}_{Fe^{2+}/Fe} = y$$ V, $$E^{0}_{Fe^{3+}/Fe} = z$$ V