Inverse Sine of $$\frac{1-x^2}{1+x^2}$$
## Formula
For $$x\ge0$$:
$$\sin^{-1}\left(\frac{1-x^2}{1+x^2}\right)=\frac\pi2-2\tan^{-1}x$$
when the resulting angle lies in the principal range of $$\sin^{-1}$$.
## Usage
- Used to transform rational expressions involving $$x^2$$ into inverse tangent form.