Inverse Tangent of a Sine Expression
## Formula
If:
$$x\in\left[-\frac\pi2,\frac\pi2\right]$$
then:
$$\tan^{-1}(\sin x)$$
is evaluated by first considering:
$$\sin x=\frac{\tan x}{\sqrt{1+\tan^2x}}$$
## Usage
- Used to transform inverse tangent expressions involving sine by introducing a suitable right-triangle relation.