Inverse Trigonometric Identity Using a Right Triangle

Rarely Tested

Inverse Trigonometric Identity Using a Right Triangle

## Formula

If:

$$\theta=\tan^{-1}x$$

then:

$$\sin\theta=\frac{x}{\sqrt{1+x^2}}$$

and:

$$\cos\theta=\frac1{\sqrt{1+x^2}}$$

## Usage

- Used as the standard substitution technique for converting between inverse tangent and sine/cosine expressions.

Question 1

Considering only the principal values of the inverse trigonometric functions, the value of

$$\cot^{-1}(\cot(-11))+10\,\sin\!\left(2\cos^{-1}\!\left(\tfrac{1}{\sqrt{2}}\right)\right)+10\sin(2\tan^{-1}(2))$$

is

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