CAT DILR Marathon Questions 2026 with Solutions PDF (Part 2)

It is given that Benitez coaches Aston Villa. Also, the person from Uruguay manages Manchester United. Since both Arsene and Sam are not from Uruguay, the manager from Uruguay can be either Moyes or Louis. But, Moyes can’t manage Manchester United as the starting letters for all three attributes are different. This means that Louis is from Uruguay and manages Manchester United. This means the manager who coaches Manchester City can be either Moyes or Sam as Arsene is not from Luxembourg. But again, Moyes can’t manage Manchester City. So Sam is from Luxembourg and manages Manchester City. Since Moyes doesn’t manage Leicester City, he must be the coach of Borussia Dortmund. This means Arsene must be managing Leicester City. Arsene can’t belong to America and the coach of Aston Villa can’t belong to America. Thus, Moyes must be from America.

The following table illustrates the complete arrangement-

From statement 7, we know that Pawan got back 30 rupees back from the counter. The only way in which this is possible is when Pawan paid 100 using two 50 rupee notes and purchased a ticket worth 70 rupees. From statement 2, we know that Amit must have purchased a 50 rupee ticket. Suresh got back rupees 10 from the counter, so he must have paid 150 and bought a 140 rupees ticket. Hence Gaurav would have also bought a 140 ticket. Moreover, before the person at the counter gave the first ticket to anyone among these six, he had 50 + 80 + 100 = 230 rupees. After the last person left the counter, the man had 60 + 260 + 500 = 820 rupees with him. Hence the 6 people purchased tickets worth 590. Since we know that Pawan, Amit, Suresh and Gaurav purchased tickets worth 70, 50, 140 and 140 respectively, so Harsh and Rohit must have bought the tickets of rupees 140 and 50 in any order (590 - 400).
We know that Rohit and Gaurav did not use 50 rupee notes. The difference between the 50 rupee notes at the beginning and at the end is 10 - 2 = 8. Hence 8 people gave 50 rupee notes to the man at the ticket counter. Pawan paid 2 fifty rupee notes and Amit paid 1 fifty rupee note. Suresh paid 3 fifty rupee notes. Hence, Harsh must have given 2 fifty rupee notes at the counter. This means that he must have purchased the fifty rupee ticket and Rohit must have purchased the 50 rupee ticket. Thus, the following table partially denotes the notes of different denomination which each person used in the transaction. A negative value implies the number of notes the person got back from the counter.

The maximum number of notes used by any person is 8. Only Gaurav can use 8 notes. This is not possible for anyone else. Hence Gaurav must have used 6 twenty rupee notes and 2 ten rupee notes. The number of 20 rupee notes with the man at the counter increased by 9. Hence both Harsh and Rohit must have given 2 notes of 20 rupees to the man at the counter. Hence we can have the following table which contains the details of the transactions.

From statement 7, we know that Pawan got back 30 rupees back from the counter. The only way in which this is possible is when Pawan paid 100 using two 50 rupee notes and purchased a ticket worth 70 rupees. From statement 2, we know that Amit must have purchased a 50 rupee ticket. Suresh got back rupees 10 from the counter, so he must have paid 150 and bought a 140 rupees ticket. Hence Gaurav would have also bought a 140 ticket. Moreover, before the person at the counter gave the first ticket to anyone among these six, he had 50 + 80 + 100 = 230 rupees. After the last person left the counter, the man had 60 + 260 + 500 = 820 rupees with him. Hence the 6 people purchased tickets worth 590. Since we know that Pawan, Amit, Suresh and Gaurav purchased tickets worth 70, 50, 140 and 140 respectively, so Harsh and Rohit must have bought the tickets of rupees 140 and 50 in any order (590 - 400).
We know that Rohit and Gaurav did not use 50 rupee notes. The difference between the 50 rupee notes at the beginning and at the end is 10 - 2 = 8. Hence 8 people gave 50 rupee notes to the man at the ticket counter. Pawan paid 2 fifty rupee notes and Amit paid 1 fifty rupee note. Suresh paid 3 fifty rupee notes. Hence, Harsh must have given 2 fifty rupee notes at the counter. This means that he must have purchased the fifty rupee ticket and Rohit must have purchased the 50 rupee ticket. Thus, the following table partially denotes the notes of different denomination which each person used in the transaction. A negative value implies the number of notes the person got back from the counter.

The maximum number of notes used by any person is 8. Only Gaurav can use 8 notes. This is not possible for anyone else. Hence Gaurav must have used 6 twenty rupee notes and 2 ten rupee notes. The number of 20 rupee notes with the man at the counter increased by 9. Hence both Harsh and Rohit must have given 2 notes of 20 rupees to the man at the counter. Hence we can have the following table which contains the details of the transactions.

We can start by making a table as shown below
We can make entries in the table using a single letter. For example: ‘D’ for Delhi, ‘M’ for Mumbai etc.

From 2, we know that Delhi is 6th in security, Chennai is 2nd in ID, Hyderabad is 4th in tourism and Pune is 3rd in cleanliness. So we can make these entries in the table.
From 1 we know that Mumbai is 3rd and Lucknow is 1st in literacy. Moreover Chennai is 4th in cleanliness. So we can make these entries in our table.
From 4, we know that either Hyderabad or Pune got the 3rd rank in security. However, Pune already has 3rd rank in cleanliness. Hence Hyderabad must be 3rd in security. Using the same logic, Mumbai is 2nd in cleanliness and Hyderabad is first in ID.
From 6, Pune is 6th in tourism, Lucknow is 3rd in ID and Hyderabad is 5th in Literacy.
Now Hyderabad can only be 6th in cleanliness. Thus, it would be second in infrastructure development. Since Pune is 6th in tourism so, Delhi must be 1 in cleanliness (condition 1). Hence Lucknow would be 5th in cleanliness. Now Lucknow can only be second in Tourism. Thus Pune will be second in security and Delhi 2nd in literacy. Now Pune will be 4th and Chennai will be 6th in literacy. Using 3, Mumbai is 1st in security. Rest of the entries can be filled in a manner like Sudoku. Thus our final table will look like the one shown below.

We can interpret the data from the graph in the following table as:

We have at the start of the 19th hour 200
Seeing the 6-hour period energy consumption we have, (200+600+800+1000+600+600) x 6 x 7= $ 159600

From condition 1, Team A is scheduled before Team D with at least one team in between them. Also, it is given that Team D is only scheduled in even numbered slots.

So, the possible slots for Team D is slot 2, 4 and 6.

If Team D is scheduled in slot 2, it means that Team A must be scheduled in slot 1. But there is no team in between Team A and Team D. So, it is not possible.

So, Team D can be scheduled in slot 4 or 6.

From condition 3, we know that Team E is scheduled after Team A and before Team B and there should be exactly two teams which are in between Team A and Team E.

It means that, there should be at least 4 slots empty before the slot of Team B. So, the earliest slot that the Team B and Team E can get is slot 5 and slot 4 respectively.

From condition 2, we know that Team B is not scheduled in the last slot (i.e. Team B can be scheduled in slot 5 and 6)

So, Team B will be scheduled in slot 5 or slot 6 when Team D is scheduled in slot 4. Similarly, when Team D is scheduled in slot 6, Team B will only be scheduled in slot 5.

Three Cases will be formed:

Case 1: Team D is scheduled in slot 4 and Team B is scheduled in slot 5.

Case 2: Team D is scheduled in slot 4 and Team B is scheduled in slot 6.

Case 3: Team D is scheduled in slot 6 and Team B is scheduled in slot 5.

In Case 1, Team B is scheduled in slot 5 and exactly 4 slots are there in front of B. It means that Team E should be at slot 4. But it is not possible as Team D is scheduled at slot 4.

So, Case 1 can be eliminated.

Remaining cases are:

Case 2: Team D is scheduled in slot 4 and Team B is scheduled in slot 6.

In this case, Team E can only be placed in slot 5.

So, Team A will be in slot 2.

Case 3: Team D is scheduled in slot 6 and Team B is scheduled in slot 5.

In this case, Team E can only be placed in slot 4.

So, Team A will be in slot 1.

From statement 4, it is known that Team G is not scheduled in the first or the last slot and Team F is scheduled after Team G.

So, in Case 2, Team G can only be in slot 3 and Team F will be in slot 7. The only remaining team, Team C will be in slot 1.

In Case 3, Team G can be in slot 2 or slot 3.

If Team G is in slot 2, Team F can be in slot 3 or slot 7. If Team F is in slot 3, Team C will be in slot 7. But it is said that Team C is scheduled before 1 p.m. Hence, it is not possible.

So, Team G will be in slot 2. Team F will be in slot 7 and Team C will be in slot 3.

If Team G is in slot 3, Team F will be in slot 7 and Team C will be in slot 2.

So, a total of 3 cases are possible which is shown below:

Now, we have to find the country from which the team leaders of each team comes from.

From statement 1, we can say that the team leaders of Team E and G are India and Japan respectively.

Similarly, from statement 3, we know that the team leader of the team which was assigned the last time slot is from Australia. So, the team leader of Team F is from Australia.

From statement 2, we know that the team leader of Team D is neither from Spain and not from China. So, the team leader of Team D can be from either England of from France.

From statement 4, we know that the team with a team leader from Spain can have the meeting in three different possible time slots.

If we look at the slots which was assigned to the different teams, Team F was assigned only 1 slot. Team A, B, D, E and G are assigned 2 slots and Team C was assigned 3 slots.

So, the only team which can held the meeting in 3 different time slots is Team C.

So, the team leader of Team C is from Spain.

From statement 5, we know that the team with the team leader from France only held the meetings in the morning slots (slot 1, 2 and 3).

So, the team leader of Team D is from England as all the possible meeting of Team D is in afternoon slots.

Now, out of the two teams left (Team A and Team B), only Team A has all its possible meetings in the morning slots. So, the team leader of Team A is from France.

The team leader of Team B will be from China.

Now, we know the the slots in which was given to all the teams for the meetings and also the countries from which the team leaders of all the teams are from.

A team leader has a flight scheduled for 5 p.m. He left for the airport 4 hours before the flight's departure. It means that he has to leave at 1 p.m.

It is given that the team leader will leave for the airport immediately after the meeting. So, the team leader was in the meeting from 12 p.m. to 1 p.m. (slot 4).

It is also given that Team A was the first team to conduct the meeting on that day.

So, the team which held their meeting in slot 4 is Team E.

The team leader of Team E is from India.

Hence, the required answer will be C