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Question 98
The volume of a right pyramid is $$45\sqrt{3} cm^3$$ and its base is an equilateral triangle with side 6 cm. What is the height(in cm)of the pyramid?
Solution
Side of equilateral triangle = 6 cm
Area of equilateral triangle = $$\frac{\sqrt{3}}{4}a^2$$Â =Â $$\frac{\sqrt{3}}{4}6^2$$ = 9$$\sqrt 3$$
The volume of a right pyramid = $$45\sqrt{3} cm^3$$
$$\frac{1}{3}$$9$$\sqrt 3$$h =Â $$45\sqrt{3} cm^3$$
h = 15 cm
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